Answer:
0.12 mole.
Explanation:
From the question given above, the following data were obtained:
Molarity of NaCl solution = 0.1 M
Volume of NaCl solution = 1.2 L
Mole of NaCl =.?
Molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:
Molarity = mole /Volume
Thus, we can obtain the mole of NaCl in the solution by using the above formula as follow:
Molarity of NaCl solution = 0.1 M
Volume of NaCl solution = 1.2 L
Mole of NaCl =.?
Molarity = mole /Volume
0.1 = mole of NaCl /1.2
Cross multiply
Mole of NaCl = 0.1 × 1.2
Mole of NaCl = 0.12 mole
Therefore, 0.12 mole of NaCl is present in the solution.
