Question

What volume (mL) of 0.2173M NaOH is required to titrate 50.00mL of 0.2980M HCI?

Answer 1

Answer: 68.6 mL

Explanation:

We need to use the equation M1V1=M2V2. Molarity's units are in L so we need to convert the 50 ml into L (divide by 1000).

.05(.298)=(x)(.2173)

x = .068 L

to convert to mL we multiply by 1000

.068*1000=68.6 mL