Question

A construction crew will build a new railroad track which passes through the point (8,5) and is parallel to the one
modeled by the line. What equation models the path of the new track?

Answer 1

Answer:

y = $-\frac{2}{9}x+\frac{61}{9}$

Step-by-step explanation:

Let the equation of the new railroad track passing through the point $(x_1,y_1)$ and slope = m₁ is,

$y-y_1=m_1(x-x_1)$

Slope of the given line = $\frac{y_2-y_1}{x_2-x_1}$

Slope of the line passing through (-3, 1) and (6, -1) will be,

m₂ = $\frac{1+1}{-3-6}$

m₂ = $-\frac{2}{9}$

Since, railroad track and the given line are parallel,

m₁ = m₂ = $-\frac{2}{9}$

Therefore, equation of the railroad track passing through (8, 5) and slope = $-\frac{2}{9}$ will be,

y - 5 = $-\frac{2}{9}(x-8)$

y = $-\frac{2}{9}x+\frac{16}{9}+5$

y = $-\frac{2}{9}x+\frac{61}{9}$

Answer 2

Answer:

BRAINLIEST PLEASEEEEEE

y-5=-2/9(x-8)

Step-by-step explanation:

I had the exact same question and just kept getting it wrong until it gave me the right one.