Someone please help me with this! Thanks :)

Answer:
[tex]y=2x+7[/tex]
Step-by-step explanation:
Given the equation
[tex]y=-\frac{1}{2}x[/tex]
comparing the equation with the slope-intercept form
[tex]y=mx+b[/tex]
Here,
so the slope of the line is -1/2
As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so
the slope of the perpendicular line will be: 2
Therefore, the point-slope form of the equation of the perpendicular line that goes through (-2, 3) is:
[tex]y-y_1=m\left(x-x_1\right)[/tex]
substituting the values m = 2 and the point (-2, 3)
[tex]y-3=2\left(x-\left(-2\right)\right)[/tex]
[tex]y-3=2\left(x+2\right)[/tex]
Add 3 to both sides
[tex]y-3+3=2\left(x+2\right)+3[/tex]
[tex]y=2x+7[/tex]