Answer:
Options (A) and (D)
Step-by-step explanation:
We can write the given division as,
[tex]\frac{2x^2+6x-8}{x+5}=2x-4+\frac{12}{x+5}[/tex]
Option (A)
When (2x² + 6x - 8) is divided (x + 5), the remainder is 12.
True.
Option (B)
When (2x² + 6x - 8) is divided (x - 5), the remainder is 12.
False.
Option (C)
When x = 5,
2x² + 6x - 8 = 12
2(5)² + 6(5) - 8 = 50 + 30 - 8
= 72
False.
Option (D)
When x = -5,
2(-5)² + 6(-5) - 8 = 50 - 30 - 8
= 12
True.
Option (E)
(x - 5) is a factor of 2x² + 6x - 8
If (x - 5) is a factor value of 2x² + 6x - 8 should be zero.
False.
Option (F)
(x + 5) is a factor of 2x² + 6x - 8
If (x + 5) is a factor then by substituting x = -5 in the expression value should be zero.
But the value is 12.
False.
