Question

A cube has a volume of 216 cubic inches, and another cube has a volume of 729 cubic inches. What is the ratio of the surface area of the larger cube to the surface area of the smaller cube?

Answer 1

Answer:

Ratio is $\frac{9}{6}$

You can simplify it of course to 3/2

Step-by-step explanation:

Volume of a cube is V = length^3 or l^3

Volume for larger cube = 729 cubic inches

Volume for smaller cube = 216 cubic inches

Surface area is S = 6*l^2

So we just need to find the length of each side of the cube.

We take the cube root for each cube volume since there are three sides.

Larger cube = 729^(1/3) = 9

smaller cube = 216^(1/3) = 6

Ratio is $\frac{9}{6}$