Question

A box has 18 candies in it: 3 are peppermint, 4 are caramel, and 11 are taffy. Jina wants to select two candies to eat for dessert. The first candy will be selected at random, and then the second candy will be selected at random from the remaining candies. What is the probability that the first candy selected is caramel and the second candy is taffy? Do not round your intermediate computations. Round your final answer to three decimal places.

Answer 1

11/18 = 0.61111111 (continuing)

3/18 = 0.166666 (continuing)

4/18 = 0.222222(continuing)

caramel = 0.2222222 x taffy = 0.6111111111

probability = 0.1358024691358, 0.136.

13.6%

Answer 2

The probability that the first candy selected is caramel and the second candy is taffy is 0.175

What is probability?

Probablity is the likelihood or chance that an event will occur.

Probability = expected/total

If a box has 18 candies in it, the total outcome will be 18

If the probability that the first candy selected is caramel is 4/18

If the probability that the second candy selected is randy is 11/18

Pr(caramel and randy) = 4/18 * 11/18

Pr(caramel and randy) = 2/9* 11/18
Pr(caramel and randy) = 11/63

Hence the probability that the first candy selected is caramel and the second candy is taffy is 0.175

Learn more on probability here: https://brainly.com/question/25870256

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