Question

Find the distance between points (3,-5) and (-2, -1) on the co-ordinate plane. Write the answer to the hundredth.

Answer 1

Distance: sqr(x2-x1)^2 + (y2-x1)^2
Sqr (-2-3)^2 + (-1+5)^2
Sqr (-1)^2 + (4)^2
Sqr 1 + 16
Sqr 17 = 4.12
The distance is 4.12
(Check my work)