Question

1.
Examine the molecule SF4 in the Real Molecules screen to check your prediction from
question c. Which interactions are more important in determining where the lone pair
will go?

Answer 1

Answer:

See explanation

Explanation:

In SF4, the lone pair is placed at an equatorial position. One needs to consider the A-B interactions (axial-equatorial) as well as the B-B (equatorial-equatorial) interactions.

The lone pair occupies an equatorial site to minimize repulsion and maximize the space between electron pairs. Remember that equatorial bonds(Xeq-E-Xeq) are at an angle of 120 degrees while axial bonds(Xax-E-Xeq) lie at an angle of 90 degrees.

Answer 2

It should be noted that in the molecule SF4, the lone pair is placed at an equatorial position.

From the complete question, it's important to consider the axial-equatorial interactions as well as the equatorial-equatorial which is the B-B interactions.

Furthermore, the lone pair occupies an equatorial site that is vital in minimizing repulsion as well as maximizing the space that's between the electron pairs.

In conclusion, the lone pair is placed at an equatorial position.

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