Answer:
Area of ΔDEF is 2.25 times the area of ΔABC.
Step-by-step explanation:
Since, ΔDEF is the enlarged form of ΔABC,
Scale factor = [tex]\frac{\text{Side length of triangle ABC}}{\text{Corresponding side length of image triangle}}[/tex]
= [tex]\frac{15}{10}[/tex]
= 1.5
Since, ratio of the areas of image and preimage triangles = (Scale factor)²
[tex]\frac{\text{Area of image triangle}}{\text{Area of triangle ABC}}[/tex] = (Scale factor)²
[tex]\frac{\text{Area of image triangle}}{\text{Area of triangle ABC}}=(1.5)^2[/tex]
Area of image ΔDEF = 2.25(Area of ΔABC)
Therefore, area of ΔDEF is 2.25 times the area of ΔABC.
