Question

Minute Math 14 (MM14) 7th Grade Math, Please Help!
I'll give brainliest to anyone who answers all questions.

Answer 1

So I saw someone only gave one of the answers. Here is mine. (Not sure why there are periods everywhere, so please ignore, none have periods)

Question 3
7, 14,21,28,35,42,49.

Question 4
42
/. \
7. 6.
/\
2. 3

Question 5 .
572, 752, 527, 725

Question 6. D
Question 7. E
Question 8. A
Question 9. B
Question 10. C

Please mark it brainliest!
If you have questions feel free to hit me up :)

Answer 2

Using the appropriate arithmetic principle, the solutions to the problems posed are as follows ;

1.)

$24 = 3 \times 2^{x}$

Divide both sides by 3

$\frac{24}{3}= 2^{x}$

$8 = 2^{x}$

$2^{3} = 2^{x}$

x = 3

2.)

$\frac{3}{5} = \frac{x}{15}$

Cross multiply

5x = 15 × 3

5x = 45

x = 9

3.)

Multiples of 7:

7 × 1 = 7

7 × 2 = 14

7 × 3 = 21

7 × 4 = 28

7 × 5 = 35

7 × 6 = 42

7 × 7 = 49

The missing multiples are : 14, 35, 42

4.)

42 = 7 × 6

6 = 2 × 3

Missing values are 7 and 3 respectively

5.)

5, 7 and 2

• 572, 725, 527, 752

6.)

$a \div 2 = \frac{a}{2}$

$a \cdot 2 = 2a$

$a^{2} = a \cdot a$

$a+a+a = 3a$

$0a = 0$

Learn more : https://brainly.com/question/17094330