Respuesta :
Answer:
[tex]a_n=-4n+10[/tex]
Step-by-step explanation:
Let us consider the given terms one by one:
First term, [tex]a[/tex] = 6
Second term, [tex]a_2=2[/tex]
Difference between First and Second term = 2 - 6 = -4
Third term, [tex]a_3[/tex] = -2
Difference between Second and Third term = -2 - 2 = -4
Fourth term, [tex]a_4[/tex] = -6
Difference between Second and Third term = -6 -(-2) = -4
Therefore, the common difference is:
[tex]d[/tex] = -4
Let the use the formula for [tex]n^{th}[/tex] term of an arithmetic sequence:
[tex]a_n=a+(n-1)d[/tex]
Putting the values of [tex]a[/tex] and [tex]d[/tex]:
[tex]a_n=6+(n-1)(-4)\\\Rightarrow a_n=6-4n+4\\\Rightarrow a_n=-4n+10[/tex]
Therefore, the [tex]n^{th}[/tex] term is:
[tex]a_n=-4n+10[/tex]
Answer:
on khan academy, b! goooood luck! :D
Step-by-step explanation: