Question

7. A gas takes up a volume of 15 liters, has a pressure of 3.3 atm, and a temperature of 299 K. If I raise the

temperature to 350 K and lower the pressure to 1050 mmHg, what is the new volume of the gas?


8. I have an unknown volume of gas held at a temperature of 115 K in a container with a pressure of 60.0

atm. If by increasing the temperature to 225 K and decreasing the pressure to 30.0 atm causes the volume

of the gas to be 25 liters, how many liters of gas did I start with?


9. A gas has a temperature of 14oC, and a volume of 5.5 liters. If the temperature is raised to 29oC and the

pressure is not changed, what is the new volume of the gas?


10. A gas that has a volume of 28 liters, a temperature of 65oC, and an unknown pressure has its volume

increased to 36 liters and its temperature decreased to 35oC. If I measure the pressure after the change to

be 2.0 atm, what was the original pressure of the gas?

Answer 1

Answer:

See explanation

Explanation:

7) P1 =3.3 atm

V1= 15 litres

T1 = 299 K

T2 = 350 K

P2 =  1050 mmHg/760 = 1.38 atm

V2?

From;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 3.3 * 15 * 350/1.38 * 299

V2 = 17325/412.62

V2 = 42 litres

8) V1= unknown

T1= 115 K

P1 = 60 atm

T2= 225 K

P2 = 30 atm

V2 = 25 litres

From;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V1 = P2V2T1/P1T2

V1 = 30 * 25 * 115/ 60 * 225

V1 = 86250/13500

V1 = 6.4 litres

9) T1 = 14 + 273 = 287 K

V1 = 5.5 liters

T2 = 29 + 273 = 302 K

V2 = the unknown

From Charles law;

V1/T1 = V2/T2

V1T2 = V2T1

V2 =V1T2/T1

V2 = 5.5 * 302/ 287

V2 = 5.8 litres

10) V1= 28 litres

T1= 65 + 273 = 338 K

P1 = the unknown

V2 = 36 liters

T2 = 35 + 273 = 308 K

P2 = 2 atm

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

P1 = P2V2T1/V1T2

P1 = 2 * 36 * 338/ 28 * 308

P1 = 24336/8624

P1 = 2.82 atm