The 99% confidence interval of the population proportion is 0.2 ± 0.0595
Confidence interval
The formula for calculating the confidence interval is expressed as:
[tex]CI = z \sqrt{\frac{p(1-p)}{n} }[/tex]
- z is the z-score for 99%CI = 2.58
- p = x/n = 60/300
- p = 0.2
Get the confidence interval
CI = 0.2 ± 2.58*√0.2(1-0.2)/300
CI = 0.2 ± 2.58√0.0005333
CI = 0.2 ± 0.0595
Hence the 99% confidence interval of the population proportion is 0.2 ± 0.0595
Learn more confidence interval here: https://brainly.com/question/15712887
