anyone know how to solve this?

Answer:
x = [tex]\sqrt{66}[/tex]
Step-by-step explanation:
This is using the altitude on hypotenuse theorem
(leg of big Δ )² = ( part of hypotenuse below it ) × ( whole hypotenuse )
x² = 6 × (6 + 5) = 6 × 11 = 66 ( take square root of both sides )
x = [tex]\sqrt{66}[/tex]
Answer:x = ≤∫⇄
Step-by-step explanation:
i think im wrong and other guy is right