Question

1. What mass can be lifted by the hydraulic press if it is known that the are:
of the small piston is 48cm and that of the large piston is 1440cm, and
the force acting on the small piston can be as large as 1000N. (use g =
10m/s)
C. 3000kg
B. 30kg
D. 30,000kg
A. 300kg
​

Answer 1

Answer:

Answer: C. 3000kg

Explanation:

Hydraulic Jack

It's a device that is used to lift heavy loads by applying force via a hydraulic cylinder.

Since the internal pressure on the liquid of the jack is constant, the following relation applies:

$\displaystyle \frac{F_1}{A_1}=\frac{F_2}{A_2}$

Where

F1  = Force applied in one end of the jack

A1  = Area of the cylinder of the same end

F2  = Force applied in the other end of the jack

A2  = Area of the cylinder of the other end

If we assume the force is being applied on side 1, then the force on side 2 is calculated by solving for F2:

$\displaystyle F_2=\frac{F_1.A_2}{A_1}$

We have F1=1000N, A1= 48~cm^2, A2= 1440~cm^2, thus:

$\displaystyle F_2=\frac{1000.1440}{48}$

$F_2 = 30000 ~N$

Since we need to know the mass that can be lifted by that force, we use the formula:

W = m.g

Where W is the weight of the mass and g= 10~m/s^2. Since the weight is equal to the force exerted by the jack:

$\displaystyle m=\frac{W}{g}=\frac{30000}{10}$

m = 3000 Kg

Answer: C. 3000kg