prakeshojha prakeshojha

30-11-2020
Mathematics

contestada

cosA - sinA / cosA + sinA= sec2 A - tan2A

Respuesta :

prayashbhatta2 prayashbhatta2

30-11-2020

Answer:

please mark me brainlist

Step-by-step explanation:

SEC2A -TAN2A

1/COS2A - SIN2A/COS2A

1-SIN2A/COS2A

1-2SINACOSA/COS^2A-SIN^2A

COS^2A+SIN^2A-2SINACOSA/COS^2A-SIN^2A

(COSA-SINA)*(COSA-SINA)/(COSA-SINA)*(COSA +SINA)

(COSA -SINA)/COSA+SINA

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