Respuesta :
Answer:
Solution given:
2=d-[tex] \frac{11}{3} [/tex]
2+[tex] \frac{11}{3} [/tex]=d
d=[tex] \frac{6+11}{3} [/tex]
d=[tex] \frac{17}{3} [/tex] or [tex] 5\frac{2}{3} [/tex]
is your answer
Answer:
Solution given:
2=d-[tex] \frac{11}{3} [/tex]
2+[tex] \frac{11}{3} [/tex]=d
d=[tex] \frac{6+11}{3} [/tex]
d=[tex] \frac{17}{3} [/tex] or [tex] 5\frac{2}{3} [/tex]
is your answer