Question

8. A tire dealer sells Supreme tires for $48 each and Prestige tires for $56 each. During one week, the sales for both tires totaled $2008. If 11 Prestige tires were sold, write and solve a linear equation to find the number of Supreme tires sold.​

Answer 1

Answer:

31 Supreme tires were sold.

Step-by-step explanation:

Cost of one Supreme tire = $45

Cost of one Prestige tire = $56

Total sales = $2008

Let x represent quantity of supreme tyre

Let y represent quantity of Prestige tyre

So, the equation will be:

$45x+56y=2008$

11 Prestige tires were sold, write and solve a linear equation to find the number of Supreme tires sold.

So, we are given y= 11 and we need to find value of x using above equation

$45x+56y=2008\\45x+56(11)=2008\\45x+616=2008\\45x=2008-616\\45x=1392\\x=\frac{1392}{45}\\x=30.933\\ x\approx31$

So, 31 Supreme tires were sold.