Question

PLEASE HELP

Solve for x 9^(x+2)=27^(8)

Answer 1

Answer:

I believe the answer is x=10

Hope this is correct! :)

Answer 2

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${9}^{(x + 2)} = {27}^{8}$

$( { {3}^{2} })^{x + 2} = ({ {3}^{3} })^{8}$

${3}^{2 \times (x + 2)} = {3}^{3 \times 8}$

${3}^{2(x + 2)} = {3}^{24}$

Thus :

$2(x + 2) = 24$

Divide sides by 2

$\frac{2(x + 2)}{2} = \frac{24}{2}$

$x + 2 = 12$

Subtract sides 2

$x + 2 - 2 = 12 - 2$

$x = 10$

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