Answer:
[tex]f\left(5\right) = 43[/tex]
Step-by-step explanation:
Given
[tex]f\left(x\right)=5x+2\mid11-5x\mid-4[/tex]
Required
Solve for x = -5
This implies that we substitute -5 for x in [tex]f\left(x\right)=5x+2\mid11-5x\mid-4[/tex]
[tex]f\left(5\right)=5(-5)+2\mid11-5(-5)\mid-4[/tex]
Open all brackets
[tex]f\left(5\right) = -25+2\mid11+25\mid-4[/tex]
[tex]f\left(5\right) = -25+2\mid36\mid-4[/tex]
Absolute value of 36 is 36; Wo, we have:
[tex]f\left(5\right) = -25+2*36-4[/tex]
[tex]f\left(5\right) = -25+72-4[/tex]
[tex]f\left(5\right) = 43[/tex]