Question

find f'(x) for f(x) = -8x2-5x-4

Thank you :)

Answer 1

Answer:

Step-by-step explanation:

Use the constant, constant multiple, and power rules for derivatives: bring down the exponent and multiply it by the constant, then replace it with an exponent that is 1 less than what it was. The derivative of

$f(x)=-8x^2-5x-4$ would look like this:

$f'(x)=-8(2)x^1-5-0$ simplifying to

$f'(x)=-16x-5$