Answer:
Percentage of HCL = 37.11 % (Approx)
Molarity = 16.17 m (Approx)
Explanation:
Given:
Molarity = 12.0 M of hcl
Density = 1.18 g/ml
Computation:
1L of hcl solution contains = 12 moles
Mass = Moles x Molar mass
Mass of HCl = 12 x 36.5
Mass of HCl = 438 g = 0.438 kg
Mass of 1 L solution = 1.18 x 1,000 ml
Mass of 1 L solution = 1180 g
Percentage of HCL = [438/1180]100
Percentage of HCL = 37.11 % (Approx)
Molarity = 12 / [1.18 - 0.438]
Molarity = 12 / [0.742]
Molarity = 16.17 m (Approx)
