Question

A car’s velocity changes from 35 m/s to stopped in 13 seconds. Calculate
acceleration.

Answer 1

Answer:

Acceleration = 3m/s^2

Vf= 0  Vi =35m/s   t= 13s

Explanation:

$Acceleration = \frac{Change in velocity}{Change in time}\\ = \frac{35m/s}{13s}\\ a = 2.69m/s^2\\ a = 2.7m/s^2\\ a = 3m/s^2$