Answer:
[tex]\frac{5}{n+1}\times \frac{n+1}{n+3}=\frac{5}{n+3}[/tex]
Step-by-step explanation:
Given the expression
[tex]\frac{5}{n+1}\times \frac{n+1}{n+3}[/tex]
Let us simplify
[tex]\frac{5}{n+1}\times \frac{n+1}{n+3}[/tex]
[tex]\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}[/tex]
[tex]=\frac{5\left(n+1\right)}{\left(n+1\right)\left(n+3\right)}[/tex]
[tex]\mathrm{Cancel\:the\:common\:factor:}\:n+1[/tex]
[tex]=\frac{5}{n+3}[/tex]
Therefore,
[tex]\frac{5}{n+1}\times \frac{n+1}{n+3}=\frac{5}{n+3}[/tex]