Answer:
The solutions to the system of equations are:
[tex]y=-8,\:x=-4[/tex]
Thus, option C is true because the point satisfies BOTH equations.
Step-by-step explanation:
Given the system of the equations
[tex]\begin{bmatrix}y=x-4\\ y=3x+4\end{bmatrix}[/tex]
Arrange equation variables for elimination
[tex]\begin{bmatrix}y-x=-4\\ y-3x=4\end{bmatrix}[/tex]
[tex]y-3x=4[/tex]
[tex]-[/tex]
[tex]\underline{y-x=-4}[/tex]
[tex]-2x=8[/tex]
[tex]\begin{bmatrix}y-x=-4\\ -2x=8\end{bmatrix}[/tex]
solve for x
[tex]-2x=8[/tex]
Divide both sides by -2
[tex]\frac{-2x}{-2}=\frac{8}{-2}[/tex]
[tex]x=-4[/tex]
[tex]\mathrm{For\:}y-x=-4\mathrm{\:plug\:in\:}x=-4[/tex]
[tex]y-\left(-4\right)=-4[/tex]
[tex]y+4=-4[/tex]
[tex]y=-8[/tex]
The solutions to the system of equations are:
[tex]y=-8,\:x=-4[/tex]
Thus, option C is true because the point satisfies BOTH equations.