Question

If, instead, the mass remained the same as the original problem, but the spring was replaced by one with a spring constant that was four times as large, the period would be:__________

Answer 1

Answer:

T = $1/2\pi \sqrt (k/m)$ so period of mass spring system becomes 2 times w.r.t original problem.

Explanation:

$T =1/2\pi \sqrt(k/m)$ so when k = 1 is replaced by 4 it means it becomes

k" = 4k

$T' = 1/2\pi \sqrt(k'/m)\\T' = 1/2\pi \sqrt(4k/m)\\T' = 2(1/2\pi\sqrt(k/m)\\)\\T' = 2T$