Answer:
Following are the solution to this question:
Explanation:
For [tex][(CH_3)_3O]^{+}[/tex]
Please find the attachment.
Calculating the formal charge[tex]= ve^{-} - (nb +\frac{b}{2})[/tex]
[tex]ve^{-} = valence\ electons\\\\nb=non \ bonding \ electrons\\\\b= bonding \ electrons[/tex]
Formal charge on [tex]C \ of \ CH_3 \ \ \ \ (1)[/tex]
[tex]= 4- (0+\frac{8}{2})\\\\= 4- (0+4)\\\\=4-4\\\\=0[/tex]
Similarly, the formal charge on all carbons atoms is = 0
The formal charge on O atom:
[tex]=6-(2+\frac{6}{2})\\\\=6-(2+3)\\\\=6-5\\\\=+1[/tex]