Question

Let p=x^2+6p=x 2 +6p, equals, x, start superscript, 2, end superscript, plus, 6. Which equation is equivalent to (x^2+6)^2-21=4x^2+24(x 2 +6) 2 ?21=4x 2 +24left parenthesis, x, start superscript, 2, end superscript, plus, 6, right parenthesis, start superscript, 2, end superscript, minus, 21, equals, 4, x, start superscript, 2, end superscript, plus, 24 in terms of p ?

Answer 1

Answer:

Step-by-step explanation:

Given p = x²+6

We are to express (x²+6)-21 = 4x²+24 in terms of p

We need to rewrite the expression first

(x²+6)²-21 = 4x²+24

Factor out 4 from the right hand side;

(x²+6)²-21 = 4(x²+6)

Replace x²+6 with p

p²+21 = 4p

Collect like terms

p²-4p = -21

p²-4p+21= 0

Hence the required equation is p²-4p+21= 0

Answer 2

Answer: p^2-4p-21=0

Step-by-step explanation:

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