Answer:
[tex](x+5)+ \dfrac{2}{x+2}[/tex]
Step-by-step explanation:
Given
[tex]\dfrac{x^2+7x+12}{x+2}[/tex]
Required
Simplify and present your answer in
[tex]p(x)+\dfrac{k}{x+2}[/tex]
First, we need to expand and factorize the numerator:
[tex]\dfrac{x^2+7x+12}{x+2}[/tex]
Express 12 as 10 + 2
[tex]\dfrac{x^2+7x+10+2}{x+2}[/tex]
Split into two using brackets
[tex]\dfrac{(x^2+7x+10)+2}{x+2}[/tex]
Split to two fractions:
[tex]\dfrac{(x^2+7x+10)}{x+2}+\dfrac{2}{x+2}[/tex]
Factorize the numerator of the first fraction
[tex]\dfrac{(x^2+5x+2x+10)}{x+2}+\dfrac{2}{x+2}[/tex]
[tex]\dfrac{x(x+5)+2(x+5)}{x+2}+\dfrac{2}{x+2}[/tex]
[tex]\dfrac{(x+2)(x+5)}{x+2}+\dfrac{2}{x+2}[/tex]
The first fraction can be simplified to give:
[tex](x+5)+ \dfrac{2}{x+2}[/tex]
Hence, by comparison:
We have simplified the given expression to the required format of:
[tex]p(x)+\dfrac{k}{x+2}[/tex]
Which implies that:
[tex]p(x) = x + 5[/tex] and [tex]k = 2[/tex]