Question

the point P has coordinates (2,1) and the point Q has coordinates(-2,-1). Find out the equation of the perpendicular bisector of PQ

Answer 1

Answer: y = -2x

M is the midpoint of PQ

=> M(0;0)

the line PQ passes through P(2;1) and Q(-2;-1)

=> (PQ): 2x - 4y = 0

have:

(d): perpendicular (PQ)

     passes throgh M(0;0)

=> (d): 4x + 2y = 0 ⇔ y = -2x

Step-by-step explanation: