Respuesta :
Answer:
[tex]t=\dfrac{9\pm 3}{6}[/tex]
[tex]1\ \text{hour}[/tex]
[tex]2\ \text{hour}[/tex]
Step-by-step explanation:
s = Speed of Emile = 6 miles/hour
d = Distance traveled by Emile = [tex](9\pm 3)\ \text{miles}[/tex]
Time taken to find the minimum and maximum time Emile ran for is
[tex]t=\dfrac{d}{s}\\\Rightarrow t=\dfrac{9\pm 3}{6}[/tex]
The required equation is [tex]t=\dfrac{9\pm 3}{6}[/tex]
The time taken is
[tex]t=\dfrac{9-3}{6}\\\Rightarrow t=\dfrac{6}{6}\\\Rightarrow t=1\ \text{hour}[/tex]
The minimum number of hours Emile runs is 1 hour.
[tex]t=\dfrac{9+3}{6}\\\Rightarrow t=\dfrac{12}{6}\\\Rightarrow t=2\ \text{hour}[/tex]
The maximum number of hours Emile runs is [tex]2\ \text{hour}[/tex].
Answer:
|6x – 9| = 3
1 Hour
2 Hours
Step-by-step explanation:
The equation that can be used to find the minimum and maximum time (in hours) Emile runs is_|6x – 9|= 3_. For each practice run, the minimum number of hours Emile runs is__1 hour_ and the maximum number of hours he runs is _2 hour.