Answer:
Esmerelda did not use the reciprocal of the divisor.
Esmerelda added the numerators.
Esmerelda added the denominators.
Explanation:
Note: This question is not complete as it omitted the work of Esmerelda. Her work is therefore provide to complete the question as follows:
[tex]\frac{-5\frac{1}{4} }{\frac{3}{2} } = \frac{-\frac{21}{4} }{\frac{3}{2} } =(-\frac{21}{4})(\frac{3}{2}) = -\frac{24}{6} = -4[/tex]
The explanation of the answer is now provided as follows:
Esmerelda did not use the reciprocal of the divisor
This is corrected by using the reciprocal of the divisor as follows:
[tex]\frac{-5\frac{1}{4} }{\frac{3}{2} } = \frac{-\frac{21}{4} }{\frac{3}{2} } =(-\frac{21}{4})(\frac{2}{3})[/tex]
Esmerelda added the numerators and Esmerelda added the denominators
These two are corrected together by multiplying the numerators separately and and multiplying the denominators separately as follows:
[tex]\frac{-5\frac{1}{4} }{\frac{3}{2} } = \frac{-\frac{21}{4} }{\frac{3\\}{2} } =(-\frac{21}{4})(\frac{2}{3}) = -\frac{21*2}{4*3}[/tex]
Based on the above, the correct answer of the work of Esmerelda can be obtained as follows:
[tex]\frac{-5\frac{1}{4} }{\frac{3}{2} } = \frac{-\frac{21}{4} }{\frac{3\\}{2} } =(-\frac{21}{4})(\frac{2}{3}) = -\frac{21*2}{4*3} =- \frac{42}{12} = -3\frac{1}{2}[/tex]
The final answer can also be provided in 2 decimal places as follows:
[tex]\frac{-5\frac{1}{4} }{\frac{3}{2} } = \frac{-\frac{21}{4} }{\frac{3\\}{2} } =(-\frac{21}{4})(\frac{2}{3}) = -\frac{21*2}{4*3} =- \frac{42}{12} = -3\frac{1}{2} = -3.50[/tex]