Question

If one ream of bondpaper costs (3x-4)pesos,how many reams can you buy for (6x^4-17x^3+24x^2-34x+24)​

Answer 1

Answer: can buy (2x³ - 3x² + 4x - 6) reams

$6x^{4} -17x^{3}+24x^{2} -34x+24\\\\\\=6x^{4}-8x^{3} -9x^{3} +12x^{2} +12x^{2} -16x-18x+24\\\\=2x^{3}(3x-4) -3x^{2} (3x-4)+4x(3x-4)-6(3x-4)\\\\\\=(2x^{3}-3x^{2} +4x-6)(3x-4)$

Step-by-step explanation:

Answer 2

The number of reams of bondpaper that can be bought from $6x^4-17x^3+24x^2-34x+24$ pesos are $2x^3-3x^2+4x-6$.

Cost of a ream of bondpaper is $(3x-4)$ pesos.

The number of reams that can be bought from $6x^4-17x^3+24x^2-34x+24$ pesos is calculated by following the long division method as-

$\dfrac{6x^4-17x^3+24x^2-34x+24}{3x-4}=2x^3-3x^2+4x-6$

So,

The number of reams that can be bought from $6x^4-17x^3+24x^2-34x+24$ pesos are $2x^3-3x^2+4x-6$.

Learn more about unitary method here:

https://brainly.com/question/19423643?referrer=searchResults