Answer:
[tex]Q=-213.84J[/tex]
Explanation:
Hello!
In this case, since energy involved when a substance undergoes a temperature change due to heat addition or removal is computed as shown below:
[tex]Q=mC\Delta T[/tex]
As the aluminum has a specific heat of 0.900 J/g°C and 14.4 g underwent such temperature decrease, the energy change is:
[tex]Q=14.4g*0.900\frac{J}{g\°C}(23.0\°C-39.5\°C)\\\\Q=-213.84J[/tex]
Which is an outlet energy flow.
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