Answer:
Explanation:
The structures of the starting materials 2‑methylhept‑3‑yne can be seen in the diagram attached below. We will also notice the role of NaNH₂ which acts as a strong base and whose function is to extract acidic proton and form an alkyne as a product.
The reaction with NaNH₂ yields acetylide ion which is then reacted with a straight-chain alkyl halide to form an extended carbon chain.
CHECK THE DIAGRAM BELOW.