Question

at what distance above the surface of the Earth is the acceleration due to Earth gravity 0.95 metre per second
square​

Answer 1

To Find :

At what distance above the surface of the Earth is the acceleration due to Earth gravity 0.95 meter per second  square​.

Solution :

Let, acceleration due to gravity at height h is $g_h$.

$\dfrac{g_h}{g}=\dfrac{R^2}{(R+h)^2}\\\\\dfrac{(R+h)}{R}=\sqrt{\dfrac{9.8}{0.95}}\\\\\dfrac{(R+h)}{R}=3.2\\\\h = 3.2R - R\\\\h = 2.2R\\\\h = 2.2\times 6400 \ km \\\\h = 14080\ km$

Therefore, the height is 14080 km.

Hence, this is the required solution.