Question

You serve a tennis ball of mass 60g at a speed of 50
m/s, what is the impulse exerted on the ball? ( ball starts from rest )

Answer 1

Answer:

$J = 3~Kg.m/s$

Explanation:

Impulse and Momentum

The impulse-momentum theorem states that the change in momentum of an object equals the impulse applied to it.

The equation can be written as follows:

$J =\Delta p = p_2-p_1$

Where:

J    = Impulse

p2 = Final Momentum

p2 = Initial Momentum

The momentum can be calculated as:

p = m.v

Where m is the mass of the object and v is the velocity.

The tennis ball with mass m=60 g = 0.06 Kg was served from rest (v1=0) to v2=50 m/s. The change in momentum is:

$\Delta p = 0.06Kg~50~m/s-0$

$\Delta p = 3~Kg.m/s$

Thus the impulse is:

$\marhbf{J = 3~Kg.m/s}$