Answer:
The inner surface area of a hemispherical bowl will be: 1923.25 cm²
Step-by-step explanation:
Given
d = 35 cm
as
[tex]r=\frac{d}{2}[/tex]
[tex]=\frac{35}{2}[/tex]
[tex]= 17.5[/tex] cm
The inner surface area of a hemispherical bowl = 2πr²
[tex]=2\times 3.14\times \left(17.5\right)^2[/tex]
[tex]=6.28\:\times \:17.5^2[/tex]
[tex]=1923.25[/tex]
Hence, the inner surface area of a hemispherical bowl will be: 1923.25 cm²
