Answer:
Step-by-step explanation:
Let 'x' be the length of a rectangle
As the width of a rectangle is 5 units less than the length.
so
width of rectangle will be = w = x - 5 units
Area = 150 square units
Using the formula
Area = length × width
[tex]150=\left(x\right)\left(x-5\right)[/tex]
[tex]150=x^2-5x[/tex]
[tex]x^2-5x=150[/tex]
Subtract 50 from both sides
[tex]x^2-5x-150=150-150[/tex]
[tex]x^2-5x-150=0[/tex]
[tex]\left(x+10\right)\left(x-15\right)=0[/tex]
if
[tex]ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)[/tex]
[tex]x+10=0\quad \mathrm{or}\quad \:x-15=0[/tex]
[tex]x=-10,\:x=15[/tex]
As length can not be negative. so
x = 15 units
Hence,
The length = x = 15 units
The width = x-5 = 15-5 = 10 units