Hi there!
[tex]\large\boxed{53) \text{ } KL = 31}\\\\\large\boxed{54) \text{ } { } DC = 3}[/tex]
53)
The altitude of a triangle is always perpendicular to the base, therefore:
5x° must equal 90°.
Solve for x:
5x = 90
5x / 5 = 90 / 5 ----> x = 18
KL is equal to 2x - 5, so plug the value of x into the equation:
KL = 2(18) - 5
KL = 36 - 5 ---> KL = 31
54)
A median bisects the base, therefore:
AD ≅ DC
Set both equations equal to each other:
3x = 2x + 1
Subtract 2x from both sides:
x = 1
Plug in the value of x into the equation for DC:
2(1) + 1 = 3.
DC = 3.
