Question

How do I solve this equation and check the solutions?

Answer 1

Answer:

The value of x is 10.

Step-by-step explanation:

The steps to do this :

$x - \sqrt{2x + 5} = 5$

$x - 5 = \sqrt{2x + 5}$

${(x - 5)}^{2} = {( \sqrt{2x + 5}) }^{2}$

${x}^{2} - 10x + 25 = 2x + 5$

${x}^{2} - 12x + 20 = 0$

${x}^{2} - 2x - 10x + 20 = 0$

$x(x - 2) - 10(x - 2) = 0$

$(x - 2)(x - 10) = 0$

$x = 2 \: (rejected)$

$x = 10$