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PLEASE HELP!!!!! 1.) Line a passes through points (-2, 1) and (2, 9). Write an equation in slope intercept form that is parallel to line a. 40POINTS

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Answer:

y=2x

Step-by-step explanation:

compute the slope  first-

(-2,1) and (2,9)

m = 9-1/2-(-2) = 8/2+2= 8/4 = 2

knowing the slope take a given point  and substitute  it's x and y values into the equation to solve for 'b' the y-intercept-

y = mx + b,

1 = 2(-2) + b,

1 = -4+ b,

b = 5

our  equation is  y = 2x + 5

if you want an equation parallel  to the line  it  has to have the same slope. Take y = 2x

Answer: y=2x+5

Step-by-step explanation:

To find line a in slope-intercept form, we first want to find the slope. The formula for slope is [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex].

[tex]m=\frac{9-1}{2-(-2)} =\frac{8}{4}=2[/tex]

Now that we know the slope, we can plug in any point to find the y-intercept.

y=2x+b       [plug in any point]

9=2(2)+b    [multiply]

9=4+b         [subtract both sides by 4]

b=5

The final equation is y=2x+5.

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