Question

g(x) = 2x^2 + 3x – 9 if g(-3)

Answer 1

Answer:

g(-3) = 0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Function Notation

Step-by-step explanation:

Step 1: Define

g(x) = 2x² + 3x - 9

g(-3) is x = -3

Step 2: Evaluate

1. Substitute:                    g(-3) = 2(-3)² + 3(-3) - 9
2. Exponents:                   g(-3) = 2(9) + 3(-3) - 9
3. Multiply:                        g(-3) = 18 - 9 - 9
4. Subtract:                       g(-3) = 9 - 9
5. Subtract:                       g(-3) = 0

Answer 2

We are looking for G(-3) not g(-3). See the difference?

Replace every x you see with -3.

G(-3) = 2(-3)^2 + 3(-3) - 9

G(-3) = 2(9) - 9 - 9

G(-3) = 18 - 18

G(-3) = 0

Got it?