Answer:
(A). [tex]\frac{15}{2}[/tex] + [tex]\frac{33}{4}[/tex] k
Step-by-step explanation:
[tex]\frac{3}{4}[/tex] × 2(2 + 4k + 3 + [tex]\frac{3}{2}[/tex] k ) = [tex]\frac{3}{2}[/tex] ( 5 + [tex]\frac{11}{2}[/tex] k ) = [tex]\frac{15}{2}[/tex] + [tex]\frac{33}{4}[/tex] k
