Find the equation that passes through points A and B

Answer:
Step-by-step explanation:
A(1,7); B(-3,-1); slope m =(-1-7)/-3-1) = -8/-4 = 2
Equation of a line AB is
((y-y1) = m(x-x1)
y - 7 = 2(x-1)
y - 7 = 2x-2
y = 2x + 5
Answer:
y = 2x +5
Step-by-step explanation:
Equation of a line
The point-slope form of the equation of a line is:
y - k = m ( x - h )
Where m is the slope and (h,k) is a point through which the line passes.
Suppose we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:
[tex]\displaystyle m=\frac{y_2-y_1}{x_2-x_1}[/tex]
The image provides two points A(1,7) and B(-3,-1), thus the slope is:
[tex]\displaystyle m=\frac{-1-7}{-3-1}[/tex]
[tex]\displaystyle m=\frac{-8}{-4}[/tex]
m = 2
Now we apply the point-slope form taking the point (1,7):
y - 7 = 2 ( x - 1 )
Operating:
y - 7 = 2x - 2
Adding 7:
y = 2x +5