Answer:
B
Step-by-step explanation:
First, let's rearrange the given equation into something more recognizable. If we add 13 to both sides, we now have the polynomial [tex]x^{2}-10x+13[/tex]. We can now use the quadratic formula to solve.
Remember that the quadratic formula is
[tex]\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}[/tex]
Substitute the numbers from the equation into the formula.
[tex]\frac{-(-10)+/-\sqrt{(-10)^{2}-4(1)(13) } }{2(1)}[/tex]
Simplify:
[tex]\frac{10+/-\sqrt{100-52} }{2}[/tex]
[tex]\frac{10+/-\sqrt{48} }{2}[/tex]
Here, I'm going to assume that there was a mistype in option B because if we divide out the 2 we end up with [tex]5+/-\sqrt{48}[/tex].
Hope this helps!