help! this is algebra 1 and idk how to do it lol

Answer:
a. x+6 = 0
b. y-2 = 0
Step-by-step explanation:
Given point is:
(-6,2)
a. Line perpendicular to x-axis:
A line perpendicular to x-axis means that the line is vertical and parallel to y-axis. Any equation parallel to y-axis has the form
x = k
where k is the x-coordinate of the point from which the line passes.
So the required equation is:
[tex]x = -6\\x+6 = 0[/tex]
b. Line perpendicular to y-axis:
A line perpendicular to y-axis will be a horizontal line parallel to x-axis having the equation of the form
y = b
where b is the y-intercept
Required equation is:
[tex]y = 2\\y-2=0[/tex]
Hence,
a. x+6 = 0
b. y-2 = 0