Answer:
F
Step-by-step explanation:
Given
[tex]\frac{a^2-b^2}{2+d^3}[/tex] ← substitute given values into the expression
= [tex]\frac{6^2-4^2}{2+(\frac{1}{2}) ^{3} }[/tex]
= [tex]\frac{36-16}{2+\frac{1}{8} }[/tex]
= [tex]\frac{20}{\frac{17}{8} }[/tex]
= [tex]\frac{20}{2.125}[/tex]
≈ 9.4118 ( to 4 dec. places ) → F
