Describe the sampling distribution of Phat. Assume the size of the Population is 25,000. N = 500 P = 0.4 Determine the Mean of the sampling distribution of Phat. Determine the standard deviation of the sampling distribution of Phat.

Answer:
0.022
Step-by-step explanation:
Given that :
Population size = 25000
n = 500 ; p = 0.4
Size of random sample (n) = 500
5% of population size : 0.05 * 25000 = 1250
Distribution is normally distributed since n < 5% of population size
Hence, the mean of the distribution = p = 0.4
Standard deviation = √((pq) /n)
q = 1 - p ; q = 1 - 0. 4 = 0.6
Standard deviation = √((0.4 * 0.6) /500)
Standard deviation = 0.0219089
= 0.022